Next, let's look at an example showing the work and calculations that are involved in converting from miles to centimeters (mi to cm). Mile to Centimeter Conversion Example Task: Convert 4 miles to centimeters (show work) Formula: mi x 160,934.4 = cm Calculations: 4 mi x 160,934.4 = 643,737.6 cm Result: 4 mi is equal to 643,737.6 cm Jul 13, 2023 · An object is 25.0 cm from the center of a spherical Part A silvered-glass Christmas tree ornament 6.40 cm in diameter. What is the position of its image (counting from the omament surface)? Follow the sign rules. Express your answer with the appropriate units. Part B What is the magnification of its image?May 29, 2023 · Example 10.2 An object, 4.0 cm in size, is placed at 25.0 cm in front of a concavemirror of focal length 15.0 cm. At what distance from the mirror should a screen be placed in order to obtain a sharp image? Findthe nature and the size of the image.Since object is always placed above princi. And the answer is 9.842519685 in in 25 cm. Likewise the question how many centimeter in 25 inch has the answer of 63.5 cm in 25 in. How much are 25 inches in centimeters? 25 inches equal 63.5 centimeters (25in = 63.5cm). Converting 25 in to cm is easy. Simply use our calculator above, or apply the formula to change the length 25 in to cm. ...Q.2 An object, 4.0 cm in size, is placed at 25.0 cm in front of a concave mirror of focal length 15.0 cm. At what distance from the mirror should a screen be...Dec 7, 2022 · An object 2.00 mm tall is placed 59.0 cm from a convex lens. The focal length of the lens has magnitude 30.0 cm. What is the height of the image in mm ? If a converging lens forms a real, inverted image 17.0 cm to the right of the lens when the object is placed 46.0 cm to the left of a lens, determine the focal length of the lens in cm. Question: A spring has a natural length of 10.0 cm. If a 25.0-N force is required to keep it stretched to a length of 24.0 cm, how much work W is required to stretch it from 10.0 cm to 17.0 cm? (Round your answer to three decimal places.) W =. There are 2 …Jun 24, 2020 · An object placed 37.5 cm in front of a 15.0-cm focal length convex lens produces an image that is 25.0 cm away from the lens. a) calculate the magnification of the image. b) If the image has a height of -3.56 cm, calculate the object's height. Chemistry questions and answers. An aqueous solution contains 0.150 M HCI at 25.0 C. The pH of the solution is a. 0.150 An aqueous solution contains 0.100 M NaOH at 25.0*C. The pH of the solution is 1. b. 1.00 c 13.00 d. 7.00 e. 0.82 2. a. 0.100 b. 1.00 c. 13.00 d. 7.00 3. Calculate the concentration (in M) of hydronium ions in a solution at 25 ... An object of height 3.0 cm is placed at 25 cm in front of a diverging lens of focal length 20 cm. Behind the diverging lens, there is a converging lens of focal length 20 cm. The distance between the lenses is 5.0 cm. Find the location and size of the final image. Since object is always placed above principal axis Height of object will be positive Height of the image = h = + 4 cm Since object is placed infront of the mirror …Heat is flowing through a rod of length 25.0 cm having cross-sectional area 8.80 cm^(2). The coefficient of thermal conductivity for the material of the rod ...A 10-cm by 15-cm rectangular wire loop carrying 820 mA is 3.0 cm from the wire, as shown in (Figure 1) . Find the magnitude of the net magnetic force on t; A force of 40 N is applied at the end of a wire 4 m long and it produces an extension of 0.24 mm. If the diameter of the wire is 2.00 mm. Calculate the (A)stress (B)strain in the wire.Physics questions and answers. An object located 25.0 cm in front of a lens forms an image on a screen 8.10 cm behind the lens. (a) Find the focal length of the lens. cm (b) Determine the magnification. ? (c) Is the lens converging or diverging? Physics questions and answers. 10. An object of height 3.00 cm is placed at 25.0 cm in front of a diverging lens of focal length 20.0 cm. Behind the diverging lens, there is a concave mirror of focal length 20.0 cm. The distance between the lens and mirror is only 5.00 cm. (a) Determine the image position due to the lens, and magnification. Since object is always placed above principal axis Height of object will be positive Height of the image = h = + 4 cm Since object is placed infront of the mirror …Physics questions and answers. 21.43 • Two point charges are separated by 25.0 cm (Fig. E21.43). Find the net electric field these charges produce at (a) point A and (b) point B. (C) What would be the magnitude and direction of the electric force this combination of charges would produce on a proton at A? Figure E21.43 6.25 nC B 12.5 nC А 10 ... Find step-by-step Chemistry solutions and your answer to the following textbook question: A 25.0-cm-long cylindrical glass tube, sealed at one end, is filled with ethanol. The mass of ethanol needed to fill the tube is found to be 45.23 g. The density of ethanol is 0.789 g/mL. Calculate the inner diameter of the tube in centimeters..Physics questions and answers. 10. An object of height 3.00 cm is placed at 25.0 cm in front of a diverging lens of focal length 20.0 cm. Behind the diverging lens, there is a concave mirror of focal length 20.0 cm. The distance between the lens and mirror is only 5.00 cm. (a) Determine the image position due to the lens, and magnification. An object 4. 0 cm in size, is placed 25. 0 cm in front of a concave mirror of focal length 15. 0 cm. The size of the image is 6 cm. The size of the object given is = 4 cm Distance of the object given in front of the mirror is = - 25 cm Focal length of the concave mirror given is = - 15 cm (focal length of concave mirror is negative) cm = km * 100000. Simply multiply 2 by 100000: cm = 2 * 100000 = 200000 cm. Therefore, 2 km equal to 200000 cm. Using the simple formulas below, you can easily convert km to cm. km to cm conversion formula: cm = km * 100000. Exercise 7.15.1 7.15. 1. Calculate the mass/volume percent of a 762.5 milliliter solution that is prepared by dissolving 289.15 grams of calcium azide, Ca (N 3) 2 , in water. Answer. 7.15: Concentrations: Mass/Volume Percent is shared under a not declared license and was authored, remixed, and/or curated by LibreTexts.Physics questions and answers. 21.43 • Two point charges are separated by 25.0 cm (Fig. E21.43). Find the net electric field these charges produce at (a) point A and (b) point B. (C) What would be the magnitude and direction of the electric force this combination of charges would produce on a proton at A? Figure E21.43 6.25 nC B 12.5 nC А 10 ...In earlier versions of Docker Engine, recursive mounts (submounts) would always be mounted as writable, even when specifying a read-only mount. This behavior has changed in v25.0.0, for hosts running on kernel version 5.12 or later. Now, read-only bind mounts are recursively read-only by default.6 days ago · How do I convert cm to m? There are 100 centimeters in a meter, and converting cm to m or vice versa is quite straightforward; here are the formulas below: To convert cm to m, you should divide your length value by 100. m = cm / 100. To convert m to cm, you need to multiply your length value by 100. cm = m × 100. An object 4.0 cm in size, is placed 25.0 cm in front of a concave mirror of a focal length of 15.0 cm. (i) At what distance from the mirror should a screen be placed in order to obtain …19 Nov 2023 ... (33-21) Two 25.0-cm-focal-length converging lenses are placed 16.5 cm apart. An object is placed 35.0 cm in front of one lens.An object 4. 0 cm in size, is placed 25. 0 cm in front of a concave mirror of focal length 15. 0 cm. The size of the image is 6 cm. The size of the object given is = 4 cm Distance of the object given in front of the mirror is = - 25 cm Focal length of the concave mirror given is = - 15 cm (focal length of concave mirror is negative)What is 25 centimeters in m? To convert 25 cm to m multiply the length in centimeters by 0.01. The 25 cm in m formula is [m] = 25 * 0.01. Thus, for 25 centimeters in meter we get 0.25 m. Aug 13, 2020 · Click here 👆 to get an answer to your question ️ An object is located 25.0 cm from a convex mirror. The image distance is -50.0 cm. What is the magnification… 19 Nov 2021 ... कोई 4.0 cm साइज का बिम्ब किसी 15.0 cm फोकस दूरी के अवतल दर्पण से 25.0 cm दूरी पर रखा है | दर्पण .Formula: multiply the value in centimeters by the conversion factor '0.393700787402'. So, 0.25 centimeter = 0.25 × 0.393700787402 = 0.0984251968505 inch. By cmtoinches.co. To use this calculator, simply type the value in any box at left or at right. It …Apr 8, 2010 · A small object is 25.0 cm from a diverging lens as shown in the figure . A converging lens with a focal length of 11.4 cm is 30.0cm to the right of the diverging lens. The two-lens system forms a real inverted image 17.0 cm to the right of the converging lens. The Attempt at a Solution 1/f = 1/o + 1/i at every step conv lens 1/12 = 1/o + 1/17.0 ... ch 13 chem. 5.0 (2 reviews) 1) Choose the statement below that is TRUE. A) A solution will form between two substances if the solute-solvent interactions are of comparable strength to the solute-solute and solvent-solvent interactions. B) A solution will form between two substances if the solute-solvent interactions are small enough to be ...Heat capacity is the amount of heat required to change the temperature of a given amount of matter by 1°C. The heat capacity of 1 gram of a substance is called its specific heat capacity (or specific heat), while the heat capacity of 1 mole of a substance is called its molar heat capacity. The amount of heat gained or lost by a sample (q) can ...Beginners should buy boots that correlate to their street shoe size. 2. Intermediate to advanced skiers should size down. 3. Ski boots should feel "suspiciously snug", as they'll pack out and get more roomy over time. 4. All brands fit a bit different, so try on a few different models to find out what fits best. 5.Science. Physics. Physics questions and answers. A 25.0 cm long spring is hung vertically from a ceiling and stretches to 29.7 cm when a 6.50 kg mass is hung from its free end. HINT (a) Find the spring constant (in N/m). N/m (b) Find the length of the spring (in cm) if the 6.50 kg weight is replaced with a 185 N weight. cm Need Help? The concepts used are the laws of reflection an …. 3. A light source is placed at a height 25.0 cm above the horizontal floor and a plane mirror of width 25.0 cm lies on the floor. The left edge of the plane mirror is 12.5 cm in front of the light source. The light rays from the light source reflects from the plane mirror and form spots on a ...Find step-by-step Chemistry solutions and your answer to the following textbook question: A 25.0-cm-long cylindrical glass tube, sealed at one end, is filled with ethanol. The mass of ethanol needed to fill the tube is found to be 45.23 g. The density of ethanol is 0.789 g/mL. Calculate the inner diameter of the tube in centimeters..Oct 15, 2020 · Therefore, internal diameter of the glass tube = 1.708 cm. Explanation: Volume of ethanol = volume of glass tube. volume of ethanol = mass of ethanol/ density of ethanol. volume of ethanol = 45.23 g/ 0.789g/ml. volume of ethanol = 57.326 ml. Therefore volume of glass tube = 57.326 ml. 1 ml = 1 cm³. Volume of glass tube in cm³ = 57.326 cm³The focal length of the objective lens of a compound microscope is 0.02 m and that of the eyepiece is 0.04 m.The distance between the objective lens and the eyepiece is 0.20 m.If the final image is formed at the least distance of distinct vision, then calculate the magnifying power of the compound microscope.Dec 29, 2019 · 7 ft 0 Inches (213 cm) 198 - 242 lb (89.8 - 109.7 kg) 225 - 275 lb (102 - 124.7 kg) See Also ...ダンロップDUNLOP テニスシューズ25.0cm DTS-1063 レッド. 長めなのと手首で搾りがあり 雨に対応している点は 丸ですが ファスナーの一番下の はめるときが なかなか ...Feb 10, 2018 · a 15.0 cm object is 12.0 cm from a concave mirror that has a focal length of 4.8 cm. its image is 8.0 cm in front of the mirror. what is the approximate height of the image produced by the mirror? A 12.0 cm object is 18.0 cm from a concave mirror that has a focal length of 9.0 cm. Next, let's look at an example showing the work and calculations that are involved in converting from miles to centimeters (mi to cm). Mile to Centimeter Conversion Example Task: Convert 4 miles to centimeters (show work) Formula: mi x 160,934.4 = cm Calculations: 4 mi x 160,934.4 = 643,737.6 cm Result: 4 mi is equal to 643,737.6 cmThe concepts used are the laws of reflection an …. 3. A light source is placed at a height 25.0 cm above the horizontal floor and a plane mirror of width 25.0 cm lies on the floor. The left edge of the plane mirror is 12.5 cm in front of the light source. The light rays from the light source reflects from the plane mirror and form spots on a ...1 day ago · A shoe size with the measure 290/120 indicates a foot length of 290 millimetres with a width of 120 millimetres. To get a certain shoe size in Canada and the United States you can use this shoe size converter formula: The length of the last, measured in inches, multiplied by three and minus a constant. The constant in question differ for mens ...The focal length of the objective lens of a compound microscope is 0.02 m and that of the eyepiece is 0.04 m.The distance between the objective lens and the eyepiece is 0.20 m.If the final image is formed at the least distance of distinct vision, then calculate the magnifying power of the compound microscope.Jul 21, 2022 · For the information you entered: Height: Weight: Your BMI is , indicating your weight is in the category for adults of your height.BMI is a screening measure and is not intended to diagnose disease or illness. For more information, visit About Adult BMI.. Discuss your BMI category with your healthcare provider as BMI may relate to your …2.5 Centimeters = 0.984251968504 Inches. 2.5 (Centimeters, cm) - unit for measure distances, lengths, heights and widths in Metric Units. One centimeter is equal to 0.393700787402 inches. On this page we consider in detail all variants for convert 2.5 centimeters to inches and all opportunities how to convert centimeters with usage ... Free online Density calculator with which you can calculate the density of any substance given its mass and volume. Density calculator in g/cm3 or g/ml and other units. The calculator can also be used to solve for mass or volume given density and the other of the two. The density calculator supports metrics in both metric and imperial units: kg, …1 Nov 2021 ... If 25.0 cm^(3) of 0.05 M Ba(NO_(3))_(2) solution is mixed with 25.0 cm^(3) of 0.02 M NaF solution. Will any BaF_(2) precipitated ?Apr 9, 2023 · Final answer: The position of the image is 26.8 cm from the ornament surface and the magnification is -0.915. Explanation: To determine the position of the image and the magnification of an object located 25.0 cm from the center of a spherical silvered-glass Christmas tree ornament with a diameter of 6.20 cm, we can use the lens equation and magnification formula for spherical mirrors. Cylindrical copper rod of length $$1\ m$$ and a cylindrical steel rod of length $$1.5\ m$$ are joined together end to end. The cross-sectional area of each rod is $$3.14\ cm^{2}$$. The free ends of steel rod and copper rods are maintained at $$0^{\circ}C$$ and $$100^{\circ}C$$ respectively. The surfaces of rods are thermally insulated.Physics for Scientists and Engineers. Physics. ISBN: 9781337553278. Author: Raymond A. Serway, John W. Jewett. Publisher: Cengage Learning. Solution for A 3.10-cm diameter coin is place 25.0 cm from a concave lens that has a focal length of -11.0 cm. determine the image distance and the diameter of…. Dec 16, 2019 · An insect 5.25 mm tall is placed 25.0 cm to the left of a thin planoconvex lens. The left surface of this lens is flat, the right surface has a radius of curvature of magnitude 12.5 cm , and the index of refraction of the lens material is 1.70. a)Calculate the location and size of the image this lens forms of the insect. CMS-1500 is a form issued by the Centers for Medicare and Medicaid Services and used by health care professionals to request reimbursement for services provided to patients. This f...This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. Question: Two point charges are separated by 25.0 cm (see (Figure 1)). Assume that q1 = -8.00 nC and q2 = -12.0 nC. Part A. Find the net electric field these charges produce at point A. Express your answer in newtons per ... The concepts used are the laws of reflection an …. 3. A light source is placed at a height 25.0 cm above the horizontal floor and a plane mirror of width 25.0 cm lies on the floor. The left edge of the plane mirror is 12.5 cm in front of the light source. The light rays from the light source reflects from the plane mirror and form spots on a ... In today’s digital age, having an effective content management system is crucial for businesses of all sizes. Content management software (CMS) allows companies to create, organize...What is 2.5 centimeters in in? To convert 2.5 cm to in multiply the length in centimeters by 0.3937007874. The 2.5 cm in in formula is [in] = 2.5 * 0.3937007874. Thus, for 2.5 centimeters in inch we get 0.9842519685 in.Apr 30, 2014 · For this question, we need to use the mirror formula 1/f= 1/d_o +1/d_i . What the problem gives us is: f = 5.0 cm, and d_o = 25.0 cm. So we are solving for d_i. Isolating the unknown to its own side of the equation, in this case by subtracting 1/d_i from both sides, will accomplish this. 1/d_i = 1/f − 1/d_o 1/d_i = 1/5 − 1/25. FInd a common denominator. 1/d_i = 5/25 − 1/25 1/d_i = 4/25 ... An object 4.0 cm in size, is placed 25.0 cm in front of a concave mirror of focal length 15.0 cm. (i) At what distance from the mirror should a screen be placed in order to obtain a sharp image? (ii) Find the size of the image. (iii) Draw a ray diagram to show the formation of image in this case.Apr 8, 2010 · A small object is 25.0 cm from a diverging lens as shown in the figure . A converging lens with a focal length of 11.4 cm is 30.0cm to the right of the diverging lens. The two-lens system forms a real inverted image 17.0 cm to the right of the converging lens. The Attempt at a Solution 1/f = 1/o + 1/i at every step conv lens 1/12 = 1/o + 1/17.0 ... Calculus questions and answers. A spring has a natural length of 10.0 cm. If a 25.0-N force is required to keep it stretched to a length of 24.0 cm, how much work W is required to stretch it from 10.0 cm to 17.0 cm? (Round your answer to three decimal places.) W =.A small object is 25.0 cm from a diverging lens as shown in the figure . A converging lens with a focal length of 12.4 cm is 30.0 cm to the right of the diverging lens. The two-lens …5 Feb 2022 ... An object 4 cm in size is placed at a distance of 25.0 cm from a concave mirror of focal length 15.0 cm. Find the position, nature and ...The CMS 1500 form is a claim form used by health care providers to file for payment of Medicare and Medicaid claims. The form is published by the Centers for Medicare and Medicaid ...Sunspots' Effect on Earth - Sunspots' effect on Earth are explained in this section. Learn about sunspots' effect on Earth. Advertisement Sunspots are connected with other solar ev...A small object is 25.0 cm from a diverging lens as shown in the figure . A converging lens with a focal length of 12.4 cm is 30.0 cm to the right of the diverging lens. The two-lens …Heat is flowing through a rod of length 25.0 cm having cross-sectional area 8.80 cm^(2). The coefficient of thermal conductivity for the material of the rod ...Final answer: The position of the image is 26.8 cm from the ornament surface and the magnification is -0.915. Explanation: To determine the position of the image and the magnification of an object located 25.0 cm from the center of a spherical silvered-glass Christmas tree ornament with a diameter of 6.20 cm, we can use the lens equation and …Although all compounds have a characteristic solubility in water at a given temperature, some families of compounds are more soluble than others and it is useful to know certain general rules of solubility. We call any substance insoluble its solubility is less than 0.01 mol/L. If its solubility is greater than 0.1 mol/L, we call it soluble.More information from the unit converter. How many cm/s in 1 m/s? The answer is 100. We assume you are converting between centimetre/second and metre/second.You can view more details on each measurement unit: cm/s or m/s The SI derived unit for speed is the meter/second. 1 cm/s is equal to 0.01 meter/second. Note that rounding errors may …About nm to cm Converter. This is a very easy to use nanometer to centimeter converter.First of all just type the nanometer (nm) value in the text field of the conversion form to start converting nm to cm, then select the decimals value and finally hit convert button if auto calculation didn't work.Centimeter value will be converted automatically as …1 day ago · A shoe size with the measure 290/120 indicates a foot length of 290 millimetres with a width of 120 millimetres. To get a certain shoe size in Canada and the United States you can use this shoe size converter formula: The length of the last, measured in inches, multiplied by three and minus a constant. The constant in question differ for mens ...A solid conducting sphere (radius = 5.0 cm) has a charge of 0.25 nC distributed uniformly on its surface. If point A is located at the center of the sphere and point B is 15 cm from the center, what is the magnitude of the electric potential difference between these two points? Oct 30, 2020 · v₁ = 17.1 cm/s. v₂ = 22.1 cm/s. Explanation: From the principle of linear momentum, the momentum is conserved. m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂. where m₁ = mass of first object = 25.0 g. u₁ = initial velocity of first object = 20 cm/s. m₂ = mass of second object = 10.0 g. u₂ = initial velocity of second object = 15.0 cm/sExpress the direction as an angle measured counterclockwise. A frog makes four jumps in a row. The displacement vectors for the four jumps are: (1) 25.5 cm, due west; (2) 24.0 cm, 32.0° south of west; (3) 25.0 cm,32.0° south of east; and (4) 34.5 cm, 34.0° north of east. What is the magnitude and direction of the frog's displacement from its ...How big is a 25 cm square? Use this easy and mobile-friendly calculator to compute the area of a square given the length of one side. calculate me. Shape Area. Contact Us. Area of a 25 Centimeter Square. What is the area of a square that is 25 centimeters on a side? How big is a 25 cm square?Oct 15, 2020 · Therefore, internal diameter of the glass tube = 1.708 cm. Explanation: Volume of ethanol = volume of glass tube. volume of ethanol = mass of ethanol/ density of ethanol. volume of ethanol = 45.23 g/ 0.789g/ml. volume of ethanol = 57.326 ml. Therefore volume of glass tube = 57.326 ml. 1 ml = 1 cm³. Volume of glass tube in cm³ = 57.326 cm³
ch 13 chem. 5.0 (2 reviews) 1) Choose the statement below that is TRUE. A) A solution will form between two substances if the solute-solvent interactions are of comparable strength to the solute-solute and solvent-solvent interactions. B) A solution will form between two substances if the solute-solvent interactions are small enough to be .... Shoprite hours near me
In the rapidly evolving world of content management systems (CMS), understanding user preferences is crucial for businesses looking to make informed decisions about their digital p...Quick conversion chart of mm to cm. 1 mm to cm = 0.1 cm. 10 mm to cm = 1 cm. 20 mm to cm = 2 cm. 30 mm to cm = 3 cm. 40 mm to cm = 4 cm. 50 mm to cm = 5 cm. 100 mm to cm = 10 cm. 200 mm to cm = 20 cm.Physics questions and answers. 10. An object of height 3.00 cm is placed at 25.0 cm in front of a diverging lens of focal length 20.0 cm. Behind the diverging lens, there is a concave mirror of focal length 20.0 cm. The distance between the lens and mirror is only 5.00 cm. (a) Determine the image position due to the lens, and magnification. The object is pulled 9.25 cm to the right of equilibrium and released from rest to slide on a horizontal, frictionless tab; A 200-g object is attached to a spring that has a force constant of 90.0 N/m. The object is pulled 8.00 cm to the right of equilibrium and released from rest to slide on a horizontal, frictionless tabTwo thin lenses with focal lengths 25.0 cm and 30.0 cm are placed in contact in an orientation so that their optic axes coincide. What is the focal length of the two in combination? (Hint: A thin lens is one whose thickness is negligible). There are 2 steps to solve this one. A solid conducting sphere (radius = 5.0 cm) has a charge of 0.25 nC distributed uniformly on its surface. If point A is located at the center of the sphere and point B is 15 cm from the center, what is the magnitude of the electric potential difference between these two points?Unlock. Previous question Next question. Transcribed image text: A solenoid 25.0 cm long and with a cross-sectional area of 0.530 cm² contains 460 turns of wire and carries a current of 80.0 A. Part A Calculate the magnetic field in the solenoid. B = 0.185 T Submit Previous Answers Correct Part B Calculate the energy density in the magnetic ...Question: A spring has a natural length of 24.0 cm. If a 25.0-N force is required to keep it stretched to a length of 42.0 cm, how much work W is required to stretch it from 24.0 cm to 33.0 cm? (Round your answer to three decimal places.) W = j Enhanced Feedback Please try again. Recall Hooke's Law: The force required to maintain a spring ...(3) An object is placed at a distance of 10 cm from a convex lens of focal length 12 cm. Find the position and nature of the image. Q. An object of height 2.0 cm is placed at a distance 20 cm in front of a concave mirror of focal length …Cylindrical copper rod of length $$1\ m$$ and a cylindrical steel rod of length $$1.5\ m$$ are joined together end to end. The cross-sectional area of each rod is $$3.14\ cm^{2}$$. The free ends of steel rod and copper rods are maintained at $$0^{\circ}C$$ and $$100^{\circ}C$$ respectively. The surfaces of rods are thermally insulated.Q.2 An object, 4.0 cm in size, is placed at 25.0 cm in front of a concave mirror of focal length 15.0 cm. At what distance from the mirror should a screen be...Jun 24, 2020 · An object placed 37.5 cm in front of a 15.0-cm focal length convex lens produces an image that is 25.0 cm away from the lens. a) calculate the magnification of the image. b) If the image has a height of -3.56 cm, calculate the object's height. Square Feet to Square Centimeter Conversion Example. Task: Convert 9 square feet to square centimeters (show work) Formula: ft 2 x 929.0304 = cm 2 Calculations: 9 ft 2 x 929.0304 = 8,361.2736 cm 2 Result: 9 ft 2 is equal to 8,361.2736 2. .